Call macro dynamically

Comments

• HubertRonald Member

  September 2017 edited September 2017

  I don't know if you need this exactly

  hiThere = function (msg) return tostring(msg) end   local g='hiThere' print(assert(loadstring('return '..g..'(...)'))("Hello World!"))   -- print: Hello World!

  @saeys you can see this link with more information about it
  https://stackoverflow.com/questions/1791234/lua-call-function-from-a-string-with-function-name

  
  [-] Liasoft

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• saeys Member

  September 2017

  Sorry for being unclear... ">
  
  I'm already doing the

  x='foo' _G[x]() -- calls foo from the global namespace

  example described in that stackoverflow link, but I would like to use macros instead of functions, for the sake of memory (and speed?). But I'm not sure if that's possible, or if possible how to call those macros dynamically.
  
  To be extra clear, right now I'm doing something like this and it's working fine:

  function snippetA() --some code end   --To call the above function letter = "A" whatToCall = "snippet" .. letter call = _G[whatToCall] call() --> "some code" get executed

  But I'd like to use macros instead:

  snippetA @ | --some code |   -- How can I call the above macro in the same manner as the function? letter = "A" whatToCall = "snippet" .. letter -- now what? The _G[whatToCall] obviously doesn't work.

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• hgy29 Maintainer

  September 2017 Accepted Answer

  @saeys, you just can't!
  Macros only exists at compile time, no longer at run time.

  Likes: antix, saeys

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• saeys Member

  September 2017

  ( @hgy29 That's a bit beyond my comprehension, but fair enough, accepting it and moving on... Thanks for quick answers!

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